How can a complete chip be 120 times shorter than an Intel 8086?
| Reference | Dimension |
|---|---|
| Intel 8086 · bare die | 6 mm longer side of the die ≈ 6 mm |
| Hitachi · 50 µm RFID chip | 50 µm side of the entire die ≈ 50 µm |
Calculation: 6 mm ÷ 50 µm, after conversion into the same unit. The ratio calculated from the catalogue data is about 120.
Both illustrations use a common factor for the stated dimension. Positions aid reading and do not represent physical separation.
The 50 micrometres describe the demonstrator’s silicon, not a self-contained RFID system: antenna and reader remain external. The ratio of 120 describes neither computing speed, power nor area; the 8086 silicon is not square.
Check the conventions
Intel 8086 · bare die
1978Commercial release
The bare Intel 8086 die measures about 6 × 5.5 mm. We compare its longer side. A newer die can be larger while containing more transistors: shrinking fabrication features does not require the processor's total area to shrink.
Documentary source linked; access was blocked by the proxy during this session. Approximate value not checked again online.
Hitachi · 50 µm RFID chip
2007Demonstration
In 2007, Hitachi presented a tiny identification circuit approximately 0.05 × 0.05 mm, or 50 × 50 µm. The entire silicon chip is represented here. The antenna and reader required for operation are not included in this dimension. This is a demonstration of miniaturization for a circuit with limited functionality, not a 50 µm general-purpose computer. The chip's size does not give the size of its transistors.
Linked source not consulted: the proxy returns CONNECT403 for this domain during this session. Approximate historical value to be checked again in an accessible source; no measurement of the illustration. Its status as a demonstrator and the exclusion of the antenna are essential to the comparison.
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